Ontem, final da tarde, sobrou meia horinha… Fui fuçar um pouco nos componentes que chegaram há meses e que ainda não havia sequer tirado da embalagem. Deu tempo de montar esta besteira… Sim, a edição do vídeo é a mais pura palhaçada!
O código, peguei aqui e modifiquei apenas as portas…
/*
* Code for cross-fading 3 LEDs, red, green and blue (RGB)
* To create fades, you need to do two things:
* 1. Describe the colors you want to be displayed
* 2. List the order you want them to fade in
*
* DESCRIBING A COLOR:
* A color is just an array of three percentages, 0-100,
* controlling the red, green and blue LEDs
*
* Red is the red LED at full, blue and green off
* int red = { 100, 0, 0 }
* Dim white is all three LEDs at 30%
* int dimWhite = {30, 30, 30}
* etc.
*
* Some common colors are provided below, or make your own
*
* LISTING THE ORDER:
* In the main part of the program, you need to list the order
* you want to colors to appear in, e.g.
* crossFade(red);
* crossFade(green);
* crossFade(blue);
*
* Those colors will appear in that order, fading out of
* one color and into the next
*
* In addition, there are 5 optional settings you can adjust:
* 1. The initial color is set to black (so the first color fades in), but
* you can set the initial color to be any other color
* 2. The internal loop runs for 1020 interations; the 'wait' variable
* sets the approximate duration of a single crossfade. In theory,
* a 'wait' of 10 ms should make a crossFade of ~10 seconds. In
* practice, the other functions the code is performing slow this
* down to ~11 seconds on my board. YMMV.
* 3. If 'repeat' is set to 0, the program will loop indefinitely.
* if it is set to a number, it will loop that number of times,
* then stop on the last color in the sequence. (Set 'return' to 1,
* and make the last color black if you want it to fade out at the end.)
* 4. There is an optional 'hold' variable, which pasues the
* program for 'hold' milliseconds when a color is complete,
* but before the next color starts.
* 5. Set the DEBUG flag to 1 if you want debugging output to be
* sent to the serial monitor.
*
* The internals of the program aren't complicated, but they
* are a little fussy -- the inner workings are explained
* below the main loop.
*
* April 2007, Clay Shirky
*/
// Output
int redPin = 9; // Red LED, connected to digital pin 9
int grnPin = 10; // Green LED, connected to digital pin 10
int bluPin = 11; // Blue LED, connected to digital pin 11
// Color arrays
int black[3] = { 0, 0, 0 };
int white[3] = { 100, 100, 100 };
int red[3] = { 100, 0, 0 };
int green[3] = { 0, 100, 0 };
int blue[3] = { 0, 0, 100 };
int yellow[3] = { 40, 95, 0 };
int dimWhite[3] = { 30, 30, 30 };
// etc.
// Set initial color
int redVal = black[0];
int grnVal = black[1];
int bluVal = black[2];
int wait = 10; // 10ms internal crossFade delay; increase for slower fades
int hold = 0; // Optional hold when a color is complete, before the next crossFade
int DEBUG = 1; // DEBUG counter; if set to 1, will write values back via serial
int loopCount = 60; // How often should DEBUG report?
int repeat = 3; // How many times should we loop before stopping? (0 for no stop)
int j = 0; // Loop counter for repeat
// Initialize color variables
int prevR = redVal;
int prevG = grnVal;
int prevB = bluVal;
// Set up the LED outputs
void setup()
{
pinMode(redPin, OUTPUT); // sets the pins as output
pinMode(grnPin, OUTPUT);
pinMode(bluPin, OUTPUT);
if (DEBUG) { // If we want to see values for debugging...
Serial.begin(9600); // ...set up the serial ouput
}
}
// Main program: list the order of crossfades
void loop()
{
crossFade(red);
crossFade(green);
crossFade(blue);
crossFade(yellow);
if (repeat) { // Do we loop a finite number of times?
j += 1;
if (j >= repeat) { // Are we there yet?
exit(j); // If so, stop.
}
}
}
/* BELOW THIS LINE IS THE MATH -- YOU SHOULDN'T NEED TO CHANGE THIS FOR THE BASICS
*
* The program works like this:
* Imagine a crossfade that moves the red LED from 0-10,
* the green from 0-5, and the blue from 10 to 7, in
* ten steps.
* We'd want to count the 10 steps and increase or
* decrease color values in evenly stepped increments.
* Imagine a + indicates raising a value by 1, and a -
* equals lowering it. Our 10 step fade would look like:
*
* 1 2 3 4 5 6 7 8 9 10
* R + + + + + + + + + +
* G + + + + +
* B - - -
*
* The red rises from 0 to 10 in ten steps, the green from
* 0-5 in 5 steps, and the blue falls from 10 to 7 in three steps.
*
* In the real program, the color percentages are converted to
* 0-255 values, and there are 1020 steps (255*4).
*
* To figure out how big a step there should be between one up- or
* down-tick of one of the LED values, we call calculateStep(),
* which calculates the absolute gap between the start and end values,
* and then divides that gap by 1020 to determine the size of the step
* between adjustments in the value.
*/
int calculateStep(int prevValue, int endValue) {
int step = endValue - prevValue; // What's the overall gap?
if (step) { // If its non-zero,
step = 1020/step; // divide by 1020
}
return step;
}
/* The next function is calculateVal. When the loop value, i,
* reaches the step size appropriate for one of the
* colors, it increases or decreases the value of that color by 1.
* (R, G, and B are each calculated separately.)
*/
int calculateVal(int step, int val, int i) {
if ((step) && i % step == 0) { // If step is non-zero and its time to change a value,
if (step > 0) { // increment the value if step is positive...
val += 1;
}
else if (step < 0) { // ...or decrement it if step is negative
val -= 1;
}
}
// Defensive driving: make sure val stays in the range 0-255
if (val > 255) {
val = 255;
}
else if (val < 0) {
val = 0;
}
return val;
}
/* crossFade() converts the percentage colors to a
* 0-255 range, then loops 1020 times, checking to see if
* the value needs to be updated each time, then writing
* the color values to the correct pins.
*/
void crossFade(int color[3]) {
// Convert to 0-255
int R = (color[0] * 255) / 100;
int G = (color[1] * 255) / 100;
int B = (color[2] * 255) / 100;
int stepR = calculateStep(prevR, R);
int stepG = calculateStep(prevG, G);
int stepB = calculateStep(prevB, B);
for (int i = 0; i <= 1020; i++) {
redVal = calculateVal(stepR, redVal, i);
grnVal = calculateVal(stepG, grnVal, i);
bluVal = calculateVal(stepB, bluVal, i);
analogWrite(redPin, redVal); // Write current values to LED pins
analogWrite(grnPin, grnVal);
analogWrite(bluPin, bluVal);
delay(wait); // Pause for 'wait' milliseconds before resuming the loop
if (DEBUG) { // If we want serial output, print it at the
if (i == 0 or i % loopCount == 0) { // beginning, and every loopCount times
Serial.print("Loop/RGB: #");
Serial.print(i);
Serial.print(" | ");
Serial.print(redVal);
Serial.print(" / ");
Serial.print(grnVal);
Serial.print(" / ");
Serial.println(bluVal);
}
DEBUG += 1;
}
}
// Update current values for next loop
prevR = redVal;
prevG = grnVal;
prevB = bluVal;
delay(hold); // Pause for optional 'wait' milliseconds before resuming the loop
}